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4x+12=-3x^2
We move all terms to the left:
4x+12-(-3x^2)=0
We get rid of parentheses
3x^2+4x+12=0
a = 3; b = 4; c = +12;
Δ = b2-4ac
Δ = 42-4·3·12
Δ = -128
Delta is less than zero, so there is no solution for the equation
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